3a^2-8a-57=0

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Solution for 3a^2-8a-57=0 equation:



3a^2-8a-57=0
a = 3; b = -8; c = -57;
Δ = b2-4ac
Δ = -82-4·3·(-57)
Δ = 748
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{748}=\sqrt{4*187}=\sqrt{4}*\sqrt{187}=2\sqrt{187}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{187}}{2*3}=\frac{8-2\sqrt{187}}{6} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{187}}{2*3}=\frac{8+2\sqrt{187}}{6} $

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